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Shrink array and replace disk all at once

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Apologies if this has been covered, I tried searching but couldn't find a definitive answer.

 

I am trying to shrink my array by two drives and I've used Unbalance(d) to move files off of these disks. My understanding is that if the disks are empty, I can remove both disks from the array at the same time and let parity rebuild once.  I was preparing to do this when another drive in my array started showing read errors, telling me it's likely time for a replacement.

 

What I'd like to do is, in one fell swoop, replace the failing drive with a new drive and remove the two empty disks from my array and only have to rebuild parity once but I want to make sure this is not a stupid thing to do.

 

I'm also open to people talking me into the alternate method for shrinking array where parity is preserved but I got the sense that method is not well tested and the scripts are not being maintained anymore.

Solved by Kilrah

  • Community Expert
  • Solution

If a drive is failing then replacing that is the most important and should be done individually before anything else. If you do a new config to shrink the array then you lose the ability to rebuild the failing drive.

Edited by Kilrah

  • Author

Thank you! I'm glad I asked. I'll get on drive replacement ASAP and won't take any other array actions until then.

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